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:<math>A_{f}=\frac{0.816}{0.1}=8.16\ m^{2}</math>
 
:<math>A_{f}=\frac{0.816}{0.1}=8.16\ m^{2}</math>
 
and the area required to settle the 1 mm particles is calculated as:
 
and the area required to settle the 1 mm particles is calculated as:
:<math<A_{f}=120\times 0.1 = 12\ m</math>
+
:<math>A_{f}=120\times 0.1 = 12\ m</math>
    
==Gallery==
 
==Gallery==
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