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→Example calculation
Line 35:
Line 35:
:<math>A_{f}=\frac{0.816}{0.1}=8.16\ m^{2}</math>
:<math>A_{f}=\frac{0.816}{0.1}=8.16\ m^{2}</math>
and the area required to settle the 1 mm particles is calculated as:
and the area required to settle the 1 mm particles is calculated as:
−:<math<A_{f}=120\times 0.1 = 12\ m</math>
+:<math>A_{f}=120\times 0.1 = 12\ m</math>
==Gallery==
==Gallery==