Changes

Jump to navigation Jump to search
m
Line 13: Line 13:  
<math>PET_{uncorrected}=1.6\cdot \left ( \frac{10\cdot T}{I} \right )^{\alpha }</math>
 
<math>PET_{uncorrected}=1.6\cdot \left ( \frac{10\cdot T}{I} \right )^{\alpha }</math>
   −
where: α = 6.75 x 10<sup>-7</sup>''I<sup>3</sup>'' - 7.71 x 10<sup>-5</sup>''I<sup>2</sup>''+ 0.0179''I'' + 0.49
+
where: α = 6.75 x 10<sup>-7</sup> ''I<sup>3</sup>'' - 7.71 x 10<sup>-5</sup> ''I<sup>2</sup>''+ 0.0179 ''I'' + 0.49
8,255

edits

Navigation menu