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| From left to right x = 12 m, x = 20 m]]<br> | | From left to right x = 12 m, x = 20 m]]<br> |
| For some geometries, particularly deep or linear facilities, it desirable to account for lateral drainage, out the sides of the storage reservoir. | | For some geometries, particularly deep or linear facilities, it desirable to account for lateral drainage, out the sides of the storage reservoir. |
− | The following equation makes use of the hydraulic radius (''A<sub>r''/''x''), where ''x'' is the perimeter (m) of the facility. <br> | + | The following equation makes use of the hydraulic radius (''A<sub>p''/''x''), where ''A<sub>p'' is the area of the facility and ''x'' is the perimeter (m) of the facility. <br> |
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| '''Maximizing the perimeter of the water storage reservoir of the facility will enhance drainage performance and directs designers towards longer, linear shapes such as [[infiltration trenches]] and [[bioswales]].''' See illustration for an example.<br> | | '''Maximizing the perimeter of the water storage reservoir of the facility will enhance drainage performance and directs designers towards longer, linear shapes such as [[infiltration trenches]] and [[bioswales]].''' See illustration for an example.<br> |
| To calculate the time (''t'') to fully drain the facility assuming three-dimensional drainage: | | To calculate the time (''t'') to fully drain the facility assuming three-dimensional drainage: |
− | <math>t=\frac{n\times A_{r}}{f'\times x}ln\left [ \frac{\left (d_{r} + \frac{A_{r}}{x} \right)}{\left (\frac{A_{r}}{x}\right) }\right]</math> | + | <math>t=\frac{n\times A_{p}}{f'\times x}ln\left [ \frac{\left (d_{r} + \frac{A_{p}}{x} \right)}{\left (\frac{A_{p}}{x}\right) }\right]</math> |
| Where "ln" means natural logarithm of the term in square brackets <br> | | Where "ln" means natural logarithm of the term in square brackets <br> |
| Adapted from CIRIA, The SUDS Manual C753 (2015). | | Adapted from CIRIA, The SUDS Manual C753 (2015). |