Changes

<math>\frac{0.008\ m \times 0.0012\ m\times6}{0.03\ m }= 0.0024\ m^{2}/m</math>

<math>\frac{0.008\ m \times 0.0012\ m\times6}{0.03\ m }= 0.0024\ m^{2}/m</math>

Then:

Then:

<math>Q_{max, p}=0.5\times 0.61\times 0.0024\ m^{2}/m\sqrt{2\cdot 9.81\ m/s^{2}\cdot \sum 1.1 m}</math>

<math>Q_{max, p}=0.5\times 0.61\times 0.0024\ m^{2}/m\sqrt{2\cdot 9.81\ m/s^{2}\cdot \sum 1.1\ m}</math>