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Sizing a triangular channel for complete volume retention:
Sizing a triangular channel for complete volume retention:
<math>L=\frac{151,400Q_{p}^{\frac{5}{8}}m^{\frac{5}{8}}S^{\frac{3}{16}}}{n^{\frac{3}{8}}\left (\sqrt{1+m^{2}} \right )^{\frac{5}{8}}f}</math>
<math>L=\frac{151,400Q_{p}^{\frac{5}{8}}m^{\frac{5}{8}}S^{\frac{3}{16}}}{n^{\frac{3}{8}}\left (\sqrt{1+m^{2}} \right )^{\frac{5}{8}}q}</math>
===Trapezoidal channel===
===Trapezoidal channel===
Sizing a trapezoidal channel for complete volume retention:
Sizing a trapezoidal channel for complete volume retention:
<math>L=\frac{360,000Q_{p}}{\left\{ b+2.388\left[\frac{Q_{p}n}{\left(2\sqrt{1+m^{2}-m}\right)S^{\frac{1}{2}}}\right ]^{\frac{3}{8}}\sqrt{1+m^{2}} \right \}f}</math>
<math>L=\frac{360,000Q_{p}}{\left\{ b+2.388\left[\frac{Q_{p}n}{\left(2\sqrt{1+m^{2}-m}\right)S^{\frac{1}{2}}}\right ]^{\frac{3}{8}}\sqrt{1+m^{2}} \right \}q}</math>
{Plainlist|1=Where:
*L = length of swale in m
*Q<sub>p</sub> = peak flow of the storm to be controlled, in m<sup>3</sup>/s
*m = swale side slope (dimensionless)
*S = the longitudinal slope (dimensionless)
*n = Manning's coefficeint (dimensionless)
*b = bottom width of trapezoidal swale, in m.}
[[category:modeling]]
[[category:modeling]]